# What is √6 over √5 in simplest radical form

answered by **Guest**

To start off, this fraction needs to be rationalized; you cant have a radical in the denominator. So, you multiply both the numerator & denominator by the same number (so as to not mess up the proportion of numerator:denominator; its like multiplying by 1) & get the radical out of the denominator. What number would that be? sqrt5.

So we have (sqrt6/sqrt5)•(sqrt5/sqrt5).

To simplify that, we get (sqrt6•sqrt5)/(sqrt5•sqrt5).

This can be rewritten as:

sqrt(6•5)/sqrt(5•5)

= sqrt30/sqrt25

Now, sqrt25 = 5, so that problem is solved as such:

sqrt30/5

Im thinking sqrt30 cant be simplified any further. If it can, do so.

Hope this helps!

If not sure about the answer, try using the search to find other answers in the subject Mathematics or ask your question yourself.

See other answers